1020000495713 has 2 divisors, whose sum is σ = 1020000495714. Its totient is φ = 1020000495712.

The previous prime is 1020000495677. The next prime is 1020000495719. The reversal of 1020000495713 is 3175940000201.

1020000495713 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 653602720849 + 366397774864 = 808457^2 + 605308^2 .

It is an emirp because it is prime and its reverse (3175940000201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1020000495713 - 2¹² = 1020000491617 is a prime.

It is a super-2 number, since 2×1020000495713² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1020000495713.

It is not a weakly prime, because it can be changed into another prime (1020000495719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510000247856 + 510000247857.

It is an arithmetic number, because the mean of its divisors is an integer number (510000247857).

Almost surely, 2^{1020000495713} is an apocalyptic number.

It is an amenable number.

1020000495713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1020000495713 is an equidigital number, since it uses as much as digits as its factorization.

1020000495713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 1020000495713 its reverse (3175940000201), we get a palindrome (4195940495914).

The spelling of 1020000495713 in words is "one trillion, twenty billion, four hundred ninety-five thousand, seven hundred thirteen".