Search a number
-
+
102012122110081 is a prime number
BaseRepresentation
bin10111001100011110001100…
…010011010001100010000001
3111101012021010012001101010211
4113030132030103101202001
5101332331311230010311
61000543415534354121
730326063324654161
oct2714361423214201
9441167105041124
10102012122110081
112a560109531757
12b53677135b941
1344bc917c27301
141b295ad5c85a1
15bbd881add821
hex5cc78c4d1881

102012122110081 has 2 divisors, whose sum is σ = 102012122110082. Its totient is φ = 102012122110080.

The previous prime is 102012122110021. The next prime is 102012122110147. The reversal of 102012122110081 is 180011221210201.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69000018890625 + 33012103219456 = 8306625^2 + 5745616^2 .

It is a cyclic number.

It is not a de Polignac number, because 102012122110081 - 235 = 101977762371713 is a prime.

It is a super-2 number, since 2×1020121221100812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102012122110021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51006061055040 + 51006061055041.

It is an arithmetic number, because the mean of its divisors is an integer number (51006061055041).

Almost surely, 2102012122110081 is an apocalyptic number.

It is an amenable number.

102012122110081 is a deficient number, since it is larger than the sum of its proper divisors (1).

102012122110081 is an equidigital number, since it uses as much as digits as its factorization.

102012122110081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 22.

Adding to 102012122110081 its reverse (180011221210201), we get a palindrome (282023343320282).

The spelling of 102012122110081 in words is "one hundred two trillion, twelve billion, one hundred twenty-two million, one hundred ten thousand, eighty-one".