Base | Representation |
---|---|
bin | 11101101100001001001… |
… | …10110000110010100111 |
3 | 10121112010202100010210011 |
4 | 32312010212300302213 |
5 | 113203212243043413 |
6 | 2100350413111051 |
7 | 133462551645202 |
oct | 16660446606247 |
9 | 3545122303704 |
10 | 1020132002983 |
11 | 3636a9a14795 |
12 | 145860188487 |
13 | 75276110842 |
14 | 37536090939 |
15 | 1b808da933d |
hex | ed849b0ca7 |
1020132002983 has 2 divisors, whose sum is σ = 1020132002984. Its totient is φ = 1020132002982.
The previous prime is 1020132002947. The next prime is 1020132003031. The reversal of 1020132002983 is 3892002310201.
1020132002983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1020132002983 - 29 = 1020132002471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1020132002933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510066001491 + 510066001492.
It is an arithmetic number, because the mean of its divisors is an integer number (510066001492).
Almost surely, 21020132002983 is an apocalyptic number.
1020132002983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1020132002983 is an equidigital number, since it uses as much as digits as its factorization.
1020132002983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 1020132002983 in words is "one trillion, twenty billion, one hundred thirty-two million, two thousand, nine hundred eighty-three".
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