Base | Representation |
---|---|
bin | 1001010001110100011110… |
… | …1100001100100101100111 |
3 | 1100010021111111122001000201 |
4 | 2110131013230030211213 |
5 | 2314121141011034411 |
6 | 33410341433451331 |
7 | 2102023610021551 |
oct | 224350754144547 |
9 | 40107444561021 |
10 | 10201750096231 |
11 | 32835a0a74441 |
12 | 1189201570b47 |
13 | 590036c140a5 |
14 | 273aa58164d1 |
15 | 12a586d643c1 |
hex | 94747b0c967 |
10201750096231 has 2 divisors, whose sum is σ = 10201750096232. Its totient is φ = 10201750096230.
The previous prime is 10201750096147. The next prime is 10201750096247. The reversal of 10201750096231 is 13269005710201.
10201750096231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10201750096231 - 27 = 10201750096103 is a prime.
It is a super-2 number, since 2×102017500962312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10201750096261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5100875048115 + 5100875048116.
It is an arithmetic number, because the mean of its divisors is an integer number (5100875048116).
Almost surely, 210201750096231 is an apocalyptic number.
10201750096231 is a deficient number, since it is larger than the sum of its proper divisors (1).
10201750096231 is an equidigital number, since it uses as much as digits as its factorization.
10201750096231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 37.
The spelling of 10201750096231 in words is "ten trillion, two hundred one billion, seven hundred fifty million, ninety-six thousand, two hundred thirty-one".
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