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102031433400133 is a prime number
BaseRepresentation
bin10111001100110000001011…
…010101111111111101000101
3111101021002222000122112221201
4113030300023111333331011
5101333140333422301013
61001000332102342501
730330346015141306
oct2714601325777505
9441232860575851
10102031433400133
112a5683192227a6
12b53a46072aa31
1344c16a4a16663
141b2a4c22347ad
15bbe1121673dd
hex5ccc0b57ff45

102031433400133 has 2 divisors, whose sum is σ = 102031433400134. Its totient is φ = 102031433400132.

The previous prime is 102031433400101. The next prime is 102031433400151. The reversal of 102031433400133 is 331004334130201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79903271732769 + 22128161667364 = 8938863^2 + 4704058^2 .

It is an emirp because it is prime and its reverse (331004334130201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102031433400133 - 25 = 102031433400101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102031433400173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51015716700066 + 51015716700067.

It is an arithmetic number, because the mean of its divisors is an integer number (51015716700067).

Almost surely, 2102031433400133 is an apocalyptic number.

It is an amenable number.

102031433400133 is a deficient number, since it is larger than the sum of its proper divisors (1).

102031433400133 is an equidigital number, since it uses as much as digits as its factorization.

102031433400133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 102031433400133 its reverse (331004334130201), we get a palindrome (433035767530334).

The spelling of 102031433400133 in words is "one hundred two trillion, thirty-one billion, four hundred thirty-three million, four hundred thousand, one hundred thirty-three".