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1020345433 is a prime number
BaseRepresentation
bin111100110100010…
…011110001011001
32122002221220210121
4330310103301121
54042202023213
6245125313241
734166536012
oct7464236131
92562856717
101020345433
11483a5a698
12245865821
131335118c3
1499726009
155e89e88d
hex3cd13c59

1020345433 has 2 divisors, whose sum is σ = 1020345434. Its totient is φ = 1020345432.

The previous prime is 1020345413. The next prime is 1020345437. The reversal of 1020345433 is 3345430201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 999065664 + 21279769 = 31608^2 + 4613^2 .

It is a cyclic number.

It is not a de Polignac number, because 1020345433 - 29 = 1020344921 is a prime.

It is a super-2 number, since 2×10203454332 = 2082209605287914978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1020345398 and 1020345407.

It is not a weakly prime, because it can be changed into another prime (1020345437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510172716 + 510172717.

It is an arithmetic number, because the mean of its divisors is an integer number (510172717).

Almost surely, 21020345433 is an apocalyptic number.

It is an amenable number.

1020345433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1020345433 is an equidigital number, since it uses as much as digits as its factorization.

1020345433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 1020345433 is about 31942.8463509437. The cubic root of 1020345433 is about 1006.7363309512.

Adding to 1020345433 its reverse (3345430201), we get a palindrome (4365775634).

The spelling of 1020345433 in words is "one billion, twenty million, three hundred forty-five thousand, four hundred thirty-three".