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102044124373 is a prime number
BaseRepresentation
bin101111100001001001…
…1011100010011010101
3100202101122000121201211
41133002103130103111
53132441243434443
6114513423421421
710241514513532
oct1370223342325
9322348017654
10102044124373
113a30527aa94
121793a454871
1398131659a9
144d20723d89
1529c391619d
hex17c24dc4d5

102044124373 has 2 divisors, whose sum is σ = 102044124374. Its totient is φ = 102044124372.

The previous prime is 102044124331. The next prime is 102044124431. The reversal of 102044124373 is 373421440201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100246957924 + 1797166449 = 316618^2 + 42393^2 .

It is an emirp because it is prime and its reverse (373421440201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102044124373 - 217 = 102043993301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102944124373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51022062186 + 51022062187.

It is an arithmetic number, because the mean of its divisors is an integer number (51022062187).

Almost surely, 2102044124373 is an apocalyptic number.

It is an amenable number.

102044124373 is a deficient number, since it is larger than the sum of its proper divisors (1).

102044124373 is an equidigital number, since it uses as much as digits as its factorization.

102044124373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 102044124373 its reverse (373421440201), we get a palindrome (475465564574).

The spelling of 102044124373 in words is "one hundred two billion, forty-four million, one hundred twenty-four thousand, three hundred seventy-three".