Base | Representation |
---|---|
bin | 10111001101110000000010… |
… | …110100110001001100111111 |
3 | 111101111122222020112010112201 |
4 | 113031300002310301030333 |
5 | 101340301310021313332 |
6 | 1001052032544012331 |
7 | 30335324266160533 |
oct | 2715600264611477 |
9 | 441448866463481 |
10 | 102100009947967 |
11 | 2a594409968119 |
12 | b54b7ba9010a7 |
13 | 44c7cb3290a05 |
14 | 1b2d949b91bc3 |
15 | bc0cc77ee5e7 |
hex | 5cdc02d3133f |
102100009947967 has 2 divisors, whose sum is σ = 102100009947968. Its totient is φ = 102100009947966.
The previous prime is 102100009947917. The next prime is 102100009947997. The reversal of 102100009947967 is 769749900001201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102100009947967 - 211 = 102100009945919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102100009947917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51050004973983 + 51050004973984.
It is an arithmetic number, because the mean of its divisors is an integer number (51050004973984).
Almost surely, 2102100009947967 is an apocalyptic number.
102100009947967 is a deficient number, since it is larger than the sum of its proper divisors (1).
102100009947967 is an equidigital number, since it uses as much as digits as its factorization.
102100009947967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1714608, while the sum is 55.
The spelling of 102100009947967 in words is "one hundred two trillion, one hundred billion, nine million, nine hundred forty-seven thousand, nine hundred sixty-seven".
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