Base | Representation |
---|---|
bin | 1001010010010011010000… |
… | …1001101101001011000011 |
3 | 1100011001211022021112002021 |
4 | 2110210310021231023003 |
5 | 2314240101112102042 |
6 | 33414225335502311 |
7 | 2102435422646323 |
oct | 224446411551303 |
9 | 40131738245067 |
10 | 10210012222147 |
11 | 32870507a7981 |
12 | 118a928527997 |
13 | 590a52853caa |
14 | 27424ac35283 |
15 | 12a8bc38b867 |
hex | 9493426d2c3 |
10210012222147 has 2 divisors, whose sum is σ = 10210012222148. Its totient is φ = 10210012222146.
The previous prime is 10210012222141. The next prime is 10210012222219. The reversal of 10210012222147 is 74122221001201.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10210012222147 is a prime.
It is a super-2 number, since 2×102100122221472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10210012222141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105006111073 + 5105006111074.
It is an arithmetic number, because the mean of its divisors is an integer number (5105006111074).
Almost surely, 210210012222147 is an apocalyptic number.
10210012222147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10210012222147 is an equidigital number, since it uses as much as digits as its factorization.
10210012222147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 10210012222147 its reverse (74122221001201), we get a palindrome (84332233223348).
The spelling of 10210012222147 in words is "ten trillion, two hundred ten billion, twelve million, two hundred twenty-two thousand, one hundred forty-seven".
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