10211100113 has 2 divisors, whose sum is σ = 10211100114. Its totient is φ = 10211100112.

The previous prime is 10211100091. The next prime is 10211100121. The reversal of 10211100113 is 31100111201.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5148493009 + 5062607104 = 71753^2 + 71152^2 .

It is an emirp because it is prime and its reverse (31100111201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10211100113 - 2¹⁰ = 10211099089 is a prime.

It is a super-2 number, since 2×10211100113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10211100094 and 10211100103.

It is not a weakly prime, because it can be changed into another prime (10211100173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105550056 + 5105550057.

It is an arithmetic number, because the mean of its divisors is an integer number (5105550057).

Almost surely, 2^10211100113 is an apocalyptic number.

It is an amenable number.

10211100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10211100113 is an equidigital number, since it uses as much as digits as its factorization.

10211100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10211100113 its reverse (31100111201), we get a palindrome (41311211314).

The spelling of 10211100113 in words is "ten billion, two hundred eleven million, one hundred thousand, one hundred thirteen".