Base | Representation |
---|---|
bin | 10111001101111010011000… |
… | …100000110000101110110011 |
3 | 111101112201121220112012002121 |
4 | 113031322120200300232303 |
5 | 101340442023433021042 |
6 | 1001101110310455111 |
7 | 30336166345344541 |
oct | 2715723040605663 |
9 | 441481556465077 |
10 | 102111111220147 |
11 | 2a599096286227 |
12 | b551998664497 |
13 | 44c9062185c13 |
14 | 1b302c02a4d91 |
15 | bc12271e5367 |
hex | 5cde98830bb3 |
102111111220147 has 2 divisors, whose sum is σ = 102111111220148. Its totient is φ = 102111111220146.
The previous prime is 102111111220109. The next prime is 102111111220163. The reversal of 102111111220147 is 741022111111201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102111111220147 - 211 = 102111111218099 is a prime.
It is a super-2 number, since 2×1021111112201472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (102111111290147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055555610073 + 51055555610074.
It is an arithmetic number, because the mean of its divisors is an integer number (51055555610074).
Almost surely, 2102111111220147 is an apocalyptic number.
102111111220147 is a deficient number, since it is larger than the sum of its proper divisors (1).
102111111220147 is an equidigital number, since it uses as much as digits as its factorization.
102111111220147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 25.
Adding to 102111111220147 its reverse (741022111111201), we get a palindrome (843133222331348).
The spelling of 102111111220147 in words is "one hundred two trillion, one hundred eleven billion, one hundred eleven million, two hundred twenty thousand, one hundred forty-seven".
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