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102111315143 is a prime number
BaseRepresentation
bin101111100011001001…
…1110000010011000111
3100202120022110021010212
41133012103300103013
53133110444041033
6114524223510035
710243261600145
oct1370623602307
9322508407125
10102111315143
113a33a1a2452
1217958a5831b
13982405c946
144d29614595
1529c9789748
hex17c64f04c7

102111315143 has 2 divisors, whose sum is σ = 102111315144. Its totient is φ = 102111315142.

The previous prime is 102111315049. The next prime is 102111315169. The reversal of 102111315143 is 341513111201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102111315143 - 214 = 102111298759 is a prime.

It is a super-2 number, since 2×1021113151432 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102111314143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055657571 + 51055657572.

It is an arithmetic number, because the mean of its divisors is an integer number (51055657572).

Almost surely, 2102111315143 is an apocalyptic number.

102111315143 is a deficient number, since it is larger than the sum of its proper divisors (1).

102111315143 is an equidigital number, since it uses as much as digits as its factorization.

102111315143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 102111315143 its reverse (341513111201), we get a palindrome (443624426344).

The spelling of 102111315143 in words is "one hundred two billion, one hundred eleven million, three hundred fifteen thousand, one hundred forty-three".