Base | Representation |
---|---|
bin | 1001010010010111101110… |
… | …0011101000001110001011 |
3 | 1100011011220210111002200102 |
4 | 2110211323203220032023 |
5 | 2314300024302344242 |
6 | 33414544252400015 |
7 | 2102510210413061 |
oct | 224457343501613 |
9 | 40134823432612 |
10 | 10211210199947 |
11 | 3287605a52379 |
12 | 118b00177600b |
13 | 590bb3ababb3 |
14 | 274321d9a031 |
15 | 12a93c627e32 |
hex | 9497b8e838b |
10211210199947 has 2 divisors, whose sum is σ = 10211210199948. Its totient is φ = 10211210199946.
The previous prime is 10211210199923. The next prime is 10211210200001. The reversal of 10211210199947 is 74999101211201.
10211210199947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10211210199947 - 210 = 10211210198923 is a prime.
It is not a weakly prime, because it can be changed into another prime (10211210199647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105605099973 + 5105605099974.
It is an arithmetic number, because the mean of its divisors is an integer number (5105605099974).
Almost surely, 210211210199947 is an apocalyptic number.
10211210199947 is a deficient number, since it is larger than the sum of its proper divisors (1).
10211210199947 is an equidigital number, since it uses as much as digits as its factorization.
10211210199947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 47.
The spelling of 10211210199947 in words is "ten trillion, two hundred eleven billion, two hundred ten million, one hundred ninety-nine thousand, nine hundred forty-seven".
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