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102112103101213 is a prime number
BaseRepresentation
bin10111001101111011010011…
…101000011111001100011101
3111101112211012000220222010101
4113031323103220133030131
5101341001041343214323
61001101352542141101
730336233051242222
oct2715732350371435
9441484160828111
10102112103101213
112a599555164147
12b552014881791
1344c918c80c7aa
141b30375cdb949
15bc1284320dad
hex5cded3a1f31d

102112103101213 has 2 divisors, whose sum is σ = 102112103101214. Its totient is φ = 102112103101212.

The previous prime is 102112103101159. The next prime is 102112103101231. The reversal of 102112103101213 is 312101301211201.

Together with next prime (102112103101231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56548550095129 + 45563553006084 = 7519877^2 + 6750078^2 .

It is a cyclic number.

It is not a de Polignac number, because 102112103101213 - 229 = 102111566230301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102112103101243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056051550606 + 51056051550607.

It is an arithmetic number, because the mean of its divisors is an integer number (51056051550607).

Almost surely, 2102112103101213 is an apocalyptic number.

It is an amenable number.

102112103101213 is a deficient number, since it is larger than the sum of its proper divisors (1).

102112103101213 is an equidigital number, since it uses as much as digits as its factorization.

102112103101213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 102112103101213 its reverse (312101301211201), we get a palindrome (414213404312414).

The spelling of 102112103101213 in words is "one hundred two trillion, one hundred twelve billion, one hundred three million, one hundred one thousand, two hundred thirteen".