1021131312013 has 2 divisors, whose sum is σ = 1021131312014. Its totient is φ = 1021131312012.

The previous prime is 1021131311987. The next prime is 1021131312029. The reversal of 1021131312013 is 3102131311201.

1021131312013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931267460484 + 89863851529 = 965022^2 + 299773^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1021131312013 is a prime.

It is a super-2 number, since 2×1021131312013² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1021131312613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510565656006 + 510565656007.

It is an arithmetic number, because the mean of its divisors is an integer number (510565656007).

Almost surely, 2^{1021131312013} is an apocalyptic number.

It is an amenable number.

1021131312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021131312013 is an equidigital number, since it uses as much as digits as its factorization.

1021131312013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1021131312013 its reverse (3102131311201), we get a palindrome (4123262623214).

The spelling of 1021131312013 in words is "one trillion, twenty-one billion, one hundred thirty-one million, three hundred twelve thousand, thirteen".