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102113131331 is a prime number
BaseRepresentation
bin101111100011001101…
…0101011101101000011
3100202120102212112111002
41133012122223231003
53133111430200311
6114524330442215
710243313203151
oct1370632535503
9322512775432
10102113131331
113a340222a32
121795959336b
139824547503
144d299683d1
1529c99e793b
hex17c66abb43

102113131331 has 2 divisors, whose sum is σ = 102113131332. Its totient is φ = 102113131330.

The previous prime is 102113131319. The next prime is 102113131333. The reversal of 102113131331 is 133131311201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102113131331 - 222 = 102108937027 is a prime.

It is a super-2 number, since 2×1021131313312 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 102113131333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (102113131333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056565665 + 51056565666.

It is an arithmetic number, because the mean of its divisors is an integer number (51056565666).

Almost surely, 2102113131331 is an apocalyptic number.

102113131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

102113131331 is an equidigital number, since it uses as much as digits as its factorization.

102113131331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 102113131331 its reverse (133131311201), we get a palindrome (235244442532).

The spelling of 102113131331 in words is "one hundred two billion, one hundred thirteen million, one hundred thirty-one thousand, three hundred thirty-one".