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102113357 is a prime number
BaseRepresentation
bin1100001011000…
…10000001001101
321010010220012012
412011202001031
5202120111412
614044351005
72346643403
oct605420115
9233126165
10102113357
1152705305
122a245465
1318203708
14d7c1473
158e70c22
hex616204d

102113357 has 2 divisors, whose sum is σ = 102113358. Its totient is φ = 102113356.

The previous prime is 102113317. The next prime is 102113371. The reversal of 102113357 is 753311201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85581001 + 16532356 = 9251^2 + 4066^2 .

It is an emirp because it is prime and its reverse (753311201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102113357 - 210 = 102112333 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102113317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056678 + 51056679.

It is an arithmetic number, because the mean of its divisors is an integer number (51056679).

Almost surely, 2102113357 is an apocalyptic number.

It is an amenable number.

102113357 is a deficient number, since it is larger than the sum of its proper divisors (1).

102113357 is an equidigital number, since it uses as much as digits as its factorization.

102113357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 23.

The square root of 102113357 is about 10105.1153877628. The cubic root of 102113357 is about 467.4058941049.

Adding to 102113357 its reverse (753311201), we get a palindrome (855424558).

The spelling of 102113357 in words is "one hundred two million, one hundred thirteen thousand, three hundred fifty-seven".