Base | Representation |
---|---|
bin | 11101101110001000101… |
… | …10110001010001010111 |
3 | 10121121220021212212212011 |
4 | 32313010112301101113 |
5 | 113212410044134341 |
6 | 2101044501205051 |
7 | 133531216655242 |
oct | 16670426612127 |
9 | 3547807785764 |
10 | 1021201552471 |
11 | 3640a8721091 |
12 | 145aba400787 |
13 | 753b688c469 |
14 | 375d8144259 |
15 | 1b86cc27b81 |
hex | edc45b1457 |
1021201552471 has 2 divisors, whose sum is σ = 1021201552472. Its totient is φ = 1021201552470.
The previous prime is 1021201552379. The next prime is 1021201552493. The reversal of 1021201552471 is 1742551021201.
It is a strong prime.
It is an emirp because it is prime and its reverse (1742551021201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1021201552471 - 211 = 1021201550423 is a prime.
It is a super-3 number, since 3×10212015524713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021201550471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510600776235 + 510600776236.
It is an arithmetic number, because the mean of its divisors is an integer number (510600776236).
Almost surely, 21021201552471 is an apocalyptic number.
1021201552471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021201552471 is an equidigital number, since it uses as much as digits as its factorization.
1021201552471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5600, while the sum is 31.
Adding to 1021201552471 its reverse (1742551021201), we get a palindrome (2763752573672).
The spelling of 1021201552471 in words is "one trillion, twenty-one billion, two hundred one million, five hundred fifty-two thousand, four hundred seventy-one".
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