Base | Representation |
---|---|
bin | 1001010010011011000101… |
… | …0100000111001011110101 |
3 | 1100011021020122120110220002 |
4 | 2110212301110013023311 |
5 | 2314303401144232013 |
6 | 33415213551321045 |
7 | 2102541441433364 |
oct | 224466124071365 |
9 | 40137218513802 |
10 | 10212112102133 |
11 | 3287a29063887 |
12 | 118b213820185 |
13 | 590cc88cc326 |
14 | 2743a9a8d7db |
15 | 12a9918cd358 |
hex | 949b15072f5 |
10212112102133 has 2 divisors, whose sum is σ = 10212112102134. Its totient is φ = 10212112102132.
The previous prime is 10212112102111. The next prime is 10212112102163. The reversal of 10212112102133 is 33120121121201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9579780194884 + 632331907249 = 3095122^2 + 795193^2 .
It is a cyclic number.
It is not a de Polignac number, because 10212112102133 - 222 = 10212107907829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10212112102163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106056051066 + 5106056051067.
It is an arithmetic number, because the mean of its divisors is an integer number (5106056051067).
Almost surely, 210212112102133 is an apocalyptic number.
It is an amenable number.
10212112102133 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212112102133 is an equidigital number, since it uses as much as digits as its factorization.
10212112102133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 10212112102133 its reverse (33120121121201), we get a palindrome (43332233223334).
The spelling of 10212112102133 in words is "ten trillion, two hundred twelve billion, one hundred twelve million, one hundred two thousand, one hundred thirty-three".
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