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10212131983 is a prime number
BaseRepresentation
bin10011000001011000…
…01100010010001111
3222100200221001111111
421200230030102033
5131403301210413
64405201232451
7511031455354
oct114054142217
928320831444
1010212131983
1143705339a9
121b90032727
13c69931861
146cc3c262b
153eb811d3d
hex260b0c48f

10212131983 has 2 divisors, whose sum is σ = 10212131984. Its totient is φ = 10212131982.

The previous prime is 10212131957. The next prime is 10212132001. The reversal of 10212131983 is 38913121201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10212131983 - 213 = 10212123791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10212138983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106065991 + 5106065992.

It is an arithmetic number, because the mean of its divisors is an integer number (5106065992).

Almost surely, 210212131983 is an apocalyptic number.

10212131983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10212131983 is an equidigital number, since it uses as much as digits as its factorization.

10212131983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 10212131983 in words is "ten billion, two hundred twelve million, one hundred thirty-one thousand, nine hundred eighty-three".