Base | Representation |
---|---|
bin | 10111001110000100100010… |
… | …010000010100101000000111 |
3 | 111101120202202121110022121012 |
4 | 113032010202100110220013 |
5 | 101341131340044214002 |
6 | 1001110112114312435 |
7 | 30340033442324624 |
oct | 2716044220245007 |
9 | 441522677408535 |
10 | 102122012101127 |
11 | 2a5a277a574477 |
12 | b553b1b28871b |
13 | 44ca0ab6b7a55 |
14 | 1b30a35d3334b |
15 | bc1664205d52 |
hex | 5ce122414a07 |
102122012101127 has 2 divisors, whose sum is σ = 102122012101128. Its totient is φ = 102122012101126.
The previous prime is 102122012101117. The next prime is 102122012101177. The reversal of 102122012101127 is 721101210221201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102122012101127 - 222 = 102122007906823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102122012101117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51061006050563 + 51061006050564.
It is an arithmetic number, because the mean of its divisors is an integer number (51061006050564).
Almost surely, 2102122012101127 is an apocalyptic number.
102122012101127 is a deficient number, since it is larger than the sum of its proper divisors (1).
102122012101127 is an equidigital number, since it uses as much as digits as its factorization.
102122012101127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 102122012101127 its reverse (721101210221201), we get a palindrome (823223222322328).
The spelling of 102122012101127 in words is "one hundred two trillion, one hundred twenty-two billion, twelve million, one hundred one thousand, one hundred twenty-seven".
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