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102131142013 is a prime number
BaseRepresentation
bin101111100011101111…
…1011000110101111101
3100202121200202120111101
41133013133120311331
53133131033021023
6114530212453101
710243622245345
oct1370737306575
9322550676441
10102131142013
113a34a40469a
121796361a191
1398281b2314
144d2c0d5d25
1529cb3a41ad
hex17c77d8d7d

102131142013 has 2 divisors, whose sum is σ = 102131142014. Its totient is φ = 102131142012.

The previous prime is 102131142007. The next prime is 102131142023. The reversal of 102131142013 is 310241131201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85321241604 + 16809900409 = 292098^2 + 129653^2 .

It is an emirp because it is prime and its reverse (310241131201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102131142013 - 29 = 102131141501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102131142023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51065571006 + 51065571007.

It is an arithmetic number, because the mean of its divisors is an integer number (51065571007).

Almost surely, 2102131142013 is an apocalyptic number.

It is an amenable number.

102131142013 is a deficient number, since it is larger than the sum of its proper divisors (1).

102131142013 is an equidigital number, since it uses as much as digits as its factorization.

102131142013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 102131142013 its reverse (310241131201), we get a palindrome (412372273214).

The spelling of 102131142013 in words is "one hundred two billion, one hundred thirty-one million, one hundred forty-two thousand, thirteen".