Base | Representation |
---|---|
bin | 1001010010011110111000… |
… | …1011011110010001100011 |
3 | 1100011100212211001001010002 |
4 | 2110213232023132101203 |
5 | 2314312444102410322 |
6 | 33415503150130215 |
7 | 2102605651144004 |
oct | 224475613362143 |
9 | 40140784031102 |
10 | 10213133247587 |
11 | 328840250a546 |
12 | 118b4597b096b |
13 | 59112c3310ca |
14 | 2744655431ab |
15 | 12aa01389c92 |
hex | 949ee2de463 |
10213133247587 has 2 divisors, whose sum is σ = 10213133247588. Its totient is φ = 10213133247586.
The previous prime is 10213133247563. The next prime is 10213133247649. The reversal of 10213133247587 is 78574233131201.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10213133247587 is a prime.
It is not a weakly prime, because it can be changed into another prime (10213133247557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106566623793 + 5106566623794.
It is an arithmetic number, because the mean of its divisors is an integer number (5106566623794).
Almost surely, 210213133247587 is an apocalyptic number.
10213133247587 is a deficient number, since it is larger than the sum of its proper divisors (1).
10213133247587 is an equidigital number, since it uses as much as digits as its factorization.
10213133247587 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 846720, while the sum is 47.
Adding to 10213133247587 its reverse (78574233131201), we get a palindrome (88787366378788).
The spelling of 10213133247587 in words is "ten trillion, two hundred thirteen billion, one hundred thirty-three million, two hundred forty-seven thousand, five hundred eighty-seven".
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