10213243331 has 2 divisors, whose sum is σ = 10213243332. Its totient is φ = 10213243330.

The previous prime is 10213243307. The next prime is 10213243333. The reversal of 10213243331 is 13334231201.

It is a strong prime.

It is an emirp because it is prime and its reverse (13334231201) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10213243331 is a prime.

It is a super-2 number, since 2×10213243331² (a number of 21 digits) contains 22 as substring.

Together with 10213243333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10213243297 and 10213243306.

It is not a weakly prime, because it can be changed into another prime (10213243333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106621665 + 5106621666.

It is an arithmetic number, because the mean of its divisors is an integer number (5106621666).

Almost surely, 2^10213243331 is an apocalyptic number.

10213243331 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213243331 is an equidigital number, since it uses as much as digits as its factorization.

10213243331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 10213243331 its reverse (13334231201), we get a palindrome (23547474532).

The spelling of 10213243331 in words is "ten billion, two hundred thirteen million, two hundred forty-three thousand, three hundred thirty-one".