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1021354451197 is a prime number
BaseRepresentation
bin11101101110011010111…
…10000010000011111101
310121122021221120221110221
432313031132002003331
5113213213214414242
62101112002301341
7133535054410153
oct16671536020375
93548257527427
101021354451197
11364176a63173
12145b41657851
137540c464892
14376105853d3
151b87b37b167
hexedcd7820fd

1021354451197 has 2 divisors, whose sum is σ = 1021354451198. Its totient is φ = 1021354451196.

The previous prime is 1021354451177. The next prime is 1021354451269. The reversal of 1021354451197 is 7911544531201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 934568826361 + 86785624836 = 966731^2 + 294594^2 .

It is a cyclic number.

It is not a de Polignac number, because 1021354451197 - 219 = 1021353926909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1021354451137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510677225598 + 510677225599.

It is an arithmetic number, because the mean of its divisors is an integer number (510677225599).

Almost surely, 21021354451197 is an apocalyptic number.

It is an amenable number.

1021354451197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021354451197 is an equidigital number, since it uses as much as digits as its factorization.

1021354451197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 43.

Adding to 1021354451197 its reverse (7911544531201), we get a palindrome (8932898982398).

The spelling of 1021354451197 in words is "one trillion, twenty-one billion, three hundred fifty-four million, four hundred fifty-one thousand, one hundred ninety-seven".