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102138116557 is a prime number
BaseRepresentation
bin101111100011111100…
…1111111100111001101
3100202122011212220202211
41133013321333213031
53133134324212212
6114531022150421
710244035444321
oct1370771774715
9322564786684
10102138116557
113a353338784
1217965a22411
139829784a79
144d2cdcd981
1529cbcd09a7
hex17c7e7f9cd

102138116557 has 2 divisors, whose sum is σ = 102138116558. Its totient is φ = 102138116556.

The previous prime is 102138116539. The next prime is 102138116699. The reversal of 102138116557 is 755611831201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82743097801 + 19395018756 = 287651^2 + 139266^2 .

It is an emirp because it is prime and its reverse (755611831201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102138116557 - 27 = 102138116429 is a prime.

It is a super-2 number, since 2×1021381165572 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102138116057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51069058278 + 51069058279.

It is an arithmetic number, because the mean of its divisors is an integer number (51069058279).

Almost surely, 2102138116557 is an apocalyptic number.

It is an amenable number.

102138116557 is a deficient number, since it is larger than the sum of its proper divisors (1).

102138116557 is an equidigital number, since it uses as much as digits as its factorization.

102138116557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 40.

Adding to 102138116557 its reverse (755611831201), we get a palindrome (857749947758).

The spelling of 102138116557 in words is "one hundred two billion, one hundred thirty-eight million, one hundred sixteen thousand, five hundred fifty-seven".