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102141531045443 is a prime number
BaseRepresentation
bin10111001110010110101101…
…101011001011111001000011
3111101122122010220210102111202
4113032112231223023321003
5101341441323421423233
61001123101021131415
730341324233526051
oct2716265553137103
9441578126712452
10102141531045443
112a5aaa864a620a
12b5578680b9b6b
1344cbb9c511346
141b319683951d1
15bc1e07aebbe8
hex5ce5adacbe43

102141531045443 has 2 divisors, whose sum is σ = 102141531045444. Its totient is φ = 102141531045442.

The previous prime is 102141531045401. The next prime is 102141531045467. The reversal of 102141531045443 is 344540135141201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102141531045443 - 220 = 102141529996867 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102141531045397 and 102141531045406.

It is not a weakly prime, because it can be changed into another prime (102141531045643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51070765522721 + 51070765522722.

It is an arithmetic number, because the mean of its divisors is an integer number (51070765522722).

Almost surely, 2102141531045443 is an apocalyptic number.

102141531045443 is a deficient number, since it is larger than the sum of its proper divisors (1).

102141531045443 is an equidigital number, since it uses as much as digits as its factorization.

102141531045443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 102141531045443 its reverse (344540135141201), we get a palindrome (446681666186644).

The spelling of 102141531045443 in words is "one hundred two trillion, one hundred forty-one billion, five hundred thirty-one million, forty-five thousand, four hundred forty-three".