Base | Representation |
---|---|
bin | 11101101110100100011… |
… | …10101011001011101111 |
3 | 10121122111111212021002111 |
4 | 32313102032223023233 |
5 | 113213344140431112 |
6 | 2101123534104451 |
7 | 133540044251566 |
oct | 16672216531357 |
9 | 3548444767074 |
10 | 1021434311407 |
11 | 364208049344 |
12 | 145b6434b127 |
13 | 75422b76443 |
14 | 3761b012bdd |
15 | 1b8833a35a7 |
hex | edd23ab2ef |
1021434311407 has 2 divisors, whose sum is σ = 1021434311408. Its totient is φ = 1021434311406.
The previous prime is 1021434311351. The next prime is 1021434311501. The reversal of 1021434311407 is 7041134341201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021434311407 - 219 = 1021433787119 is a prime.
It is a congruent number.
It is a weakly prime.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510717155703 + 510717155704.
It is an arithmetic number, because the mean of its divisors is an integer number (510717155704).
Almost surely, 21021434311407 is an apocalyptic number.
1021434311407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021434311407 is an equidigital number, since it uses as much as digits as its factorization.
1021434311407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 1021434311407 its reverse (7041134341201), we get a palindrome (8062568652608).
The spelling of 1021434311407 in words is "one trillion, twenty-one billion, four hundred thirty-four million, three hundred eleven thousand, four hundred seven".
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