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102159692413 is a prime number
BaseRepresentation
bin101111100100100110…
…0010011001001111101
3100202200200111002021121
41133021030103021331
53133210340124123
6114533112430541
710244420025562
oct1371114231175
9322620432247
10102159692413
113a364534a69
12179710a8451
13983109a54c
144d31c08869
1529cdb4375d
hex17c931327d

102159692413 has 2 divisors, whose sum is σ = 102159692414. Its totient is φ = 102159692412.

The previous prime is 102159692363. The next prime is 102159692431. The reversal of 102159692413 is 314296951201.

Together with next prime (102159692431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97745020164 + 4414672249 = 312642^2 + 66443^2 .

It is a cyclic number.

It is not a de Polignac number, because 102159692413 - 217 = 102159561341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 102159692413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102159692473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51079846206 + 51079846207.

It is an arithmetic number, because the mean of its divisors is an integer number (51079846207).

Almost surely, 2102159692413 is an apocalyptic number.

It is an amenable number.

102159692413 is a deficient number, since it is larger than the sum of its proper divisors (1).

102159692413 is an equidigital number, since it uses as much as digits as its factorization.

102159692413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 43.

The spelling of 102159692413 in words is "one hundred two billion, one hundred fifty-nine million, six hundred ninety-two thousand, four hundred thirteen".