Base | Representation |
---|---|
bin | 11101101111000000010… |
… | …10011111001110111011 |
3 | 10121200002210202200202122 |
4 | 32313200022133032323 |
5 | 113214334013014112 |
6 | 2101203044551455 |
7 | 133545613343255 |
oct | 16674012371673 |
9 | 3550083680678 |
10 | 1021668094907 |
11 | 364318006349 |
12 | 14600a6b258b |
13 | 7545c42b885 |
14 | 376400aacd5 |
15 | 1b898b82872 |
hex | ede029f3bb |
1021668094907 has 2 divisors, whose sum is σ = 1021668094908. Its totient is φ = 1021668094906.
The previous prime is 1021668094901. The next prime is 1021668094969. The reversal of 1021668094907 is 7094908661201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021668094907 - 214 = 1021668078523 is a prime.
It is not a weakly prime, because it can be changed into another prime (1021668094901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510834047453 + 510834047454.
It is an arithmetic number, because the mean of its divisors is an integer number (510834047454).
Almost surely, 21021668094907 is an apocalyptic number.
1021668094907 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021668094907 is an equidigital number, since it uses as much as digits as its factorization.
1021668094907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 53.
The spelling of 1021668094907 in words is "one trillion, twenty-one billion, six hundred sixty-eight million, ninety-four thousand, nine hundred seven".
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