Search a number
-
+
102201111120012 = 2238516759260001
BaseRepresentation
bin10111001111001110001100…
…111011001000100010001100
3111101212022221011012210212020
4113033032030323020202030
5101343430333421320022
61001210313045010140
730345533544023262
oct2717161473104214
9441768834183766
10102201111120012
112a62327a939063
12b5673153b3950
1345046a5c71738
141b347bb178432
15bc374355235c
hex5cf38cec888c

102201111120012 has 12 divisors (see below), whose sum is σ = 238469259280056. Its totient is φ = 34067037040000.

The previous prime is 102201111119969. The next prime is 102201111120041. The reversal of 102201111120012 is 210021111102201.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×1022011111200122 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 102201111119973 and 102201111120000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4258379629989 + ... + 4258379630012.

It is an arithmetic number, because the mean of its divisors is an integer number (19872438273338).

Almost surely, 2102201111120012 is an apocalyptic number.

102201111120012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

102201111120012 is an abundant number, since it is smaller than the sum of its proper divisors (136268148160044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102201111120012 is a wasteful number, since it uses less digits than its factorization.

102201111120012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8516759260008 (or 8516759260006 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 102201111120012 its reverse (210021111102201), we get a palindrome (312222222222213).

The spelling of 102201111120012 in words is "one hundred two trillion, two hundred one billion, one hundred eleven million, one hundred twenty thousand, twelve".

Divisors: 1 2 3 4 6 12 8516759260001 17033518520002 25550277780003 34067037040004 51100555560006 102201111120012