Base | Representation |
---|---|
bin | 10111001111001110010100… |
… | …000100110111101111001001 |
3 | 111101212100020112000002111221 |
4 | 113033032110010313233021 |
5 | 101343431110131110121 |
6 | 1001210333012522041 |
7 | 30345536531655445 |
oct | 2717162404675711 |
9 | 441770215002457 |
10 | 102201231113161 |
11 | 2a623331645754 |
12 | b567349620321 |
13 | 45046c4a954bb |
14 | 1b347cd091825 |
15 | bc374dd55b41 |
hex | 5cf394137bc9 |
102201231113161 has 2 divisors, whose sum is σ = 102201231113162. Its totient is φ = 102201231113160.
The previous prime is 102201231113123. The next prime is 102201231113227. The reversal of 102201231113161 is 161311132102201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90099487805625 + 12101743307536 = 9492075^2 + 3478756^2 .
It is a cyclic number.
It is not a de Polignac number, because 102201231113161 - 213 = 102201231104969 is a prime.
It is not a weakly prime, because it can be changed into another prime (102201231116161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51100615556580 + 51100615556581.
It is an arithmetic number, because the mean of its divisors is an integer number (51100615556581).
Almost surely, 2102201231113161 is an apocalyptic number.
It is an amenable number.
102201231113161 is a deficient number, since it is larger than the sum of its proper divisors (1).
102201231113161 is an equidigital number, since it uses as much as digits as its factorization.
102201231113161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 102201231113161 its reverse (161311132102201), we get a palindrome (263512363215362).
The spelling of 102201231113161 in words is "one hundred two trillion, two hundred one billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred sixty-one".
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