Base | Representation |
---|---|
bin | 101111100101110101… |
… | …1001011000110010001 |
3 | 100202210120212000110010 |
4 | 1133023223023012101 |
5 | 3133302020342210 |
6 | 114541201225133 |
7 | 10245434026161 |
oct | 1371353130621 |
9 | 322716760403 |
10 | 102201340305 |
11 | 3a385aa0709 |
12 | 179830321a9 |
13 | 98398c017c |
14 | 4d3756a5a1 |
15 | 29d261d920 |
hex | 17cbacb191 |
102201340305 has 64 divisors (see below), whose sum is σ = 172772425728. Its totient is φ = 51485829120.
The previous prime is 102201340261. The next prime is 102201340337. The reversal of 102201340305 is 503043102201.
It is not a de Polignac number, because 102201340305 - 217 = 102201209233 is a prime.
It is a super-3 number, since 3×1022013403053 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 16294320 + ... + 16300590.
It is an arithmetic number, because the mean of its divisors is an integer number (2699569152).
Almost surely, 2102201340305 is an apocalyptic number.
102201340305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
102201340305 is a deficient number, since it is larger than the sum of its proper divisors (70571085423).
102201340305 is a wasteful number, since it uses less digits than its factorization.
102201340305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6886.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 102201340305 its reverse (503043102201), we get a palindrome (605244442506).
The spelling of 102201340305 in words is "one hundred two billion, two hundred one million, three hundred forty thousand, three hundred five".
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