Base | Representation |
---|---|
bin | 10111001111001111001110… |
… | …011011000100011111111011 |
3 | 111101212102202201222021002022 |
4 | 113033033032123010133323 |
5 | 101343440111230324011 |
6 | 1001211014102025055 |
7 | 30345603016320416 |
oct | 2717171633043773 |
9 | 441772681867068 |
10 | 102202210011131 |
11 | 2a62379416623a |
12 | b56758141818b |
13 | 450481c824779 |
14 | 1b348830a8b7d |
15 | bc37a9c698db |
hex | 5cf3ce6c47fb |
102202210011131 has 2 divisors, whose sum is σ = 102202210011132. Its totient is φ = 102202210011130.
The previous prime is 102202210011119. The next prime is 102202210011137. The reversal of 102202210011131 is 131110012202201.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102202210011131 - 226 = 102202142902267 is a prime.
It is a super-2 number, since 2×1022022100111312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (102202210011137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51101105005565 + 51101105005566.
It is an arithmetic number, because the mean of its divisors is an integer number (51101105005566).
Almost surely, 2102202210011131 is an apocalyptic number.
102202210011131 is a deficient number, since it is larger than the sum of its proper divisors (1).
102202210011131 is an equidigital number, since it uses as much as digits as its factorization.
102202210011131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 102202210011131 its reverse (131110012202201), we get a palindrome (233312222213332).
The spelling of 102202210011131 in words is "one hundred two trillion, two hundred two billion, two hundred ten million, eleven thousand, one hundred thirty-one".
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