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102202210011131 is a prime number
BaseRepresentation
bin10111001111001111001110…
…011011000100011111111011
3111101212102202201222021002022
4113033033032123010133323
5101343440111230324011
61001211014102025055
730345603016320416
oct2717171633043773
9441772681867068
10102202210011131
112a62379416623a
12b56758141818b
13450481c824779
141b348830a8b7d
15bc37a9c698db
hex5cf3ce6c47fb

102202210011131 has 2 divisors, whose sum is σ = 102202210011132. Its totient is φ = 102202210011130.

The previous prime is 102202210011119. The next prime is 102202210011137. The reversal of 102202210011131 is 131110012202201.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102202210011131 - 226 = 102202142902267 is a prime.

It is a super-2 number, since 2×1022022100111312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102202210011137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51101105005565 + 51101105005566.

It is an arithmetic number, because the mean of its divisors is an integer number (51101105005566).

Almost surely, 2102202210011131 is an apocalyptic number.

102202210011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

102202210011131 is an equidigital number, since it uses as much as digits as its factorization.

102202210011131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 102202210011131 its reverse (131110012202201), we get a palindrome (233312222213332).

The spelling of 102202210011131 in words is "one hundred two trillion, two hundred two billion, two hundred ten million, eleven thousand, one hundred thirty-one".