Base | Representation |
---|---|
bin | 10111001111010000010110… |
… | …000000111111011011000011 |
3 | 111101212112212110002122002221 |
4 | 113033100112000333123003 |
5 | 101344000041222243042 |
6 | 1001211333210151511 |
7 | 30345644542563661 |
oct | 2717202600773303 |
9 | 441775773078087 |
10 | 102203411134147 |
11 | 2a624250169794 |
12 | b567857722597 |
13 | 450498162014b |
14 | 1b3495880bc31 |
15 | bc382a427d67 |
hex | 5cf41603f6c3 |
102203411134147 has 2 divisors, whose sum is σ = 102203411134148. Its totient is φ = 102203411134146.
The previous prime is 102203411134133. The next prime is 102203411134151. The reversal of 102203411134147 is 741431114302201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102203411134147 - 211 = 102203411132099 is a prime.
It is not a weakly prime, because it can be changed into another prime (102203411434147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51101705567073 + 51101705567074.
It is an arithmetic number, because the mean of its divisors is an integer number (51101705567074).
Almost surely, 2102203411134147 is an apocalyptic number.
102203411134147 is a deficient number, since it is larger than the sum of its proper divisors (1).
102203411134147 is an equidigital number, since it uses as much as digits as its factorization.
102203411134147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 102203411134147 its reverse (741431114302201), we get a palindrome (843634525436348).
The spelling of 102203411134147 in words is "one hundred two trillion, two hundred three billion, four hundred eleven million, one hundred thirty-four thousand, one hundred forty-seven".
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