Base | Representation |
---|---|
bin | 1001010010111100111110… |
… | …1010000010011111011111 |
3 | 1100012010201202221112000201 |
4 | 2110233033222002133133 |
5 | 2314431020020214101 |
6 | 33423320510404331 |
7 | 2103313065600331 |
oct | 224571752023737 |
9 | 40163652845021 |
10 | 10221211101151 |
11 | 3290878222486 |
12 | 1190b32b006a7 |
13 | 591b18a3260b |
14 | 2749d02b5451 |
15 | 12ad25612e01 |
hex | 94bcfa827df |
10221211101151 has 2 divisors, whose sum is σ = 10221211101152. Its totient is φ = 10221211101150.
The previous prime is 10221211101109. The next prime is 10221211101169. The reversal of 10221211101151 is 15110111212201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10221211101151 - 211 = 10221211099103 is a prime.
It is a super-3 number, since 3×102212111011513 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10221211101181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5110605550575 + 5110605550576.
It is an arithmetic number, because the mean of its divisors is an integer number (5110605550576).
Almost surely, 210221211101151 is an apocalyptic number.
10221211101151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10221211101151 is an equidigital number, since it uses as much as digits as its factorization.
10221211101151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 19.
Adding to 10221211101151 its reverse (15110111212201), we get a palindrome (25331322313352).
The spelling of 10221211101151 in words is "ten trillion, two hundred twenty-one billion, two hundred eleven million, one hundred one thousand, one hundred fifty-one".
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