Base | Representation |
---|---|
bin | 10011000010100100… |
… | …10011000010011001 |
3 | 222101101201120000021 |
4 | 21201102103002121 |
5 | 131413330333423 |
6 | 4410155310441 |
7 | 511212411241 |
oct | 114122230231 |
9 | 28341646007 |
10 | 10222121113 |
11 | 4376136986 |
12 | 1b9344b421 |
13 | c6ba1b499 |
14 | 6cd862b21 |
15 | 3ec63695d |
hex | 261493099 |
10222121113 has 2 divisors, whose sum is σ = 10222121114. Its totient is φ = 10222121112.
The previous prime is 10222121111. The next prime is 10222121123. The reversal of 10222121113 is 31112122201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6170416704 + 4051704409 = 78552^2 + 63653^2 .
It is a cyclic number.
It is not a de Polignac number, because 10222121113 - 21 = 10222121111 is a prime.
Together with 10222121111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10222121111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111060556 + 5111060557.
It is an arithmetic number, because the mean of its divisors is an integer number (5111060557).
Almost surely, 210222121113 is an apocalyptic number.
It is an amenable number.
10222121113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10222121113 is an equidigital number, since it uses as much as digits as its factorization.
10222121113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10222121113 its reverse (31112122201), we get a palindrome (41334243314).
The spelling of 10222121113 in words is "ten billion, two hundred twenty-two million, one hundred twenty-one thousand, one hundred thirteen".
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