Base | Representation |
---|---|
bin | 10111001111111001010010… |
… | …110100000100110000001111 |
3 | 111102000202100202211200021221 |
4 | 113033321102310010300033 |
5 | 101400210113443044442 |
6 | 1001243444233304211 |
7 | 30352062262051501 |
oct | 2717712264046017 |
9 | 442022322750257 |
10 | 102247380831247 |
11 | 2a640963993a33 |
12 | b574288b65067 |
13 | 4508b6ac442b2 |
14 | 1b36b2a2c1d71 |
15 | bc4a5069b467 |
hex | 5cfe52d04c0f |
102247380831247 has 2 divisors, whose sum is σ = 102247380831248. Its totient is φ = 102247380831246.
The previous prime is 102247380831187. The next prime is 102247380831311. The reversal of 102247380831247 is 742138083742201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102247380831247 - 235 = 102213021092879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102247380831194 and 102247380831203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102247380831647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51123690415623 + 51123690415624.
It is an arithmetic number, because the mean of its divisors is an integer number (51123690415624).
Almost surely, 2102247380831247 is an apocalyptic number.
102247380831247 is a deficient number, since it is larger than the sum of its proper divisors (1).
102247380831247 is an equidigital number, since it uses as much as digits as its factorization.
102247380831247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3612672, while the sum is 52.
The spelling of 102247380831247 in words is "one hundred two trillion, two hundred forty-seven billion, three hundred eighty million, eight hundred thirty-one thousand, two hundred forty-seven".
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