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10230131143 is a prime number
BaseRepresentation
bin10011000011100001…
…10110100111000111
3222101221210111201001
421201300312213013
5131422403144033
64411043114131
7511340452141
oct114160664707
928357714631
1010230131143
11437a707a41
121b96072947
13c7059434b
146d0949c91
153ed1b9e7d
hex261c369c7

10230131143 has 2 divisors, whose sum is σ = 10230131144. Its totient is φ = 10230131142.

The previous prime is 10230131111. The next prime is 10230131201. The reversal of 10230131143 is 34113103201.

10230131143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10230131143 - 25 = 10230131111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10230131143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10230131243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115065571 + 5115065572.

It is an arithmetic number, because the mean of its divisors is an integer number (5115065572).

Almost surely, 210230131143 is an apocalyptic number.

10230131143 is a deficient number, since it is larger than the sum of its proper divisors (1).

10230131143 is an equidigital number, since it uses as much as digits as its factorization.

10230131143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10230131143 its reverse (34113103201), we get a palindrome (44343234344).

The spelling of 10230131143 in words is "ten billion, two hundred thirty million, one hundred thirty-one thousand, one hundred forty-three".