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102302309504873 is a prime number
BaseRepresentation
bin10111010000101100011100…
…110100010101011101101001
3111102020000010211211102002102
4113100230130310111131221
5101402110112213123443
61001325010541343145
730356045412062222
oct2720543464253551
9442200124742072
10102302309504873
112a662190777475
12b582a58567ab5
1345110b2b2b43a
141b3965b428249
15bc61b7aa8cb8
hex5d0b1cd15769

102302309504873 has 2 divisors, whose sum is σ = 102302309504874. Its totient is φ = 102302309504872.

The previous prime is 102302309504809. The next prime is 102302309504911. The reversal of 102302309504873 is 378405903203201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102281102281744 + 21207223129 = 10113412^2 + 145627^2 .

It is an emirp because it is prime and its reverse (378405903203201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102302309504873 - 26 = 102302309504809 is a prime.

It is a super-2 number, since 2×1023023095048732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102302309504273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51151154752436 + 51151154752437.

It is an arithmetic number, because the mean of its divisors is an integer number (51151154752437).

Almost surely, 2102302309504873 is an apocalyptic number.

It is an amenable number.

102302309504873 is a deficient number, since it is larger than the sum of its proper divisors (1).

102302309504873 is an equidigital number, since it uses as much as digits as its factorization.

102302309504873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 47.

The spelling of 102302309504873 in words is "one hundred two trillion, three hundred two billion, three hundred nine million, five hundred four thousand, eight hundred seventy-three".