Base | Representation |
---|---|
bin | 10111010000101111000100… |
… | …111011101101111010111011 |
3 | 111102020021102102010000222012 |
4 | 113100233010323231322323 |
5 | 101402131401240343342 |
6 | 1001330154454520135 |
7 | 30356205331022123 |
oct | 2720570473557273 |
9 | 442207372100865 |
10 | 102305130012347 |
11 | 2a6633a8891489 |
12 | b58350506604b |
13 | 4511442288a82 |
14 | 1b39847c69c83 |
15 | bc62d04e4b82 |
hex | 5d0bc4eedebb |
102305130012347 has 2 divisors, whose sum is σ = 102305130012348. Its totient is φ = 102305130012346.
The previous prime is 102305130012289. The next prime is 102305130012367. The reversal of 102305130012347 is 743210031503201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102305130012347 - 222 = 102305125818043 is a prime.
It is a super-3 number, since 3×1023051300123473 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (102305130012367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51152565006173 + 51152565006174.
It is an arithmetic number, because the mean of its divisors is an integer number (51152565006174).
Almost surely, 2102305130012347 is an apocalyptic number.
102305130012347 is a deficient number, since it is larger than the sum of its proper divisors (1).
102305130012347 is an equidigital number, since it uses as much as digits as its factorization.
102305130012347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 102305130012347 its reverse (743210031503201), we get a palindrome (845515161515548).
The spelling of 102305130012347 in words is "one hundred two trillion, three hundred five billion, one hundred thirty million, twelve thousand, three hundred forty-seven".
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