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10232123117 is a prime number
BaseRepresentation
bin10011000011110000…
…11100111011101101
3222102002112201011212
421201320130323231
5131423410414432
64411153524205
7511363416506
oct114170347355
928362481155
1010232123117
1143808485a7
121b96873665
13c70b10c28
146d0d07bad
153ed4602b2
hex261e1ceed

10232123117 has 2 divisors, whose sum is σ = 10232123118. Its totient is φ = 10232123116.

The previous prime is 10232123059. The next prime is 10232123129. The reversal of 10232123117 is 71132123201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5829933316 + 4402189801 = 76354^2 + 66349^2 .

It is an emirp because it is prime and its reverse (71132123201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10232123117 - 214 = 10232106733 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10232123092 and 10232123101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10232123617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5116061558 + 5116061559.

It is an arithmetic number, because the mean of its divisors is an integer number (5116061559).

Almost surely, 210232123117 is an apocalyptic number.

It is an amenable number.

10232123117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10232123117 is an equidigital number, since it uses as much as digits as its factorization.

10232123117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 10232123117 its reverse (71132123201), we get a palindrome (81364246318).

The spelling of 10232123117 in words is "ten billion, two hundred thirty-two million, one hundred twenty-three thousand, one hundred seventeen".