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10232143313981 is a prime number
BaseRepresentation
bin1001010011100101101101…
…0001000111110000111101
31100020011221122211110202012
42110321123101013300331
52320120412142021411
633432325353541005
72104151023064051
oct224713321076075
940204848743665
1010232143313981
113295478170816
121193084114765
13592b6b8b46c4
1427534a17bc61
1512b26526218b
hex94e5b447c3d

10232143313981 has 2 divisors, whose sum is σ = 10232143313982. Its totient is φ = 10232143313980.

The previous prime is 10232143313923. The next prime is 10232143314037. The reversal of 10232143313981 is 18931334123201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9714074461081 + 518068852900 = 3116741^2 + 719770^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10232143313981 is a prime.

It is a super-2 number, since 2×102321433139812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10234143313981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5116071656990 + 5116071656991.

It is an arithmetic number, because the mean of its divisors is an integer number (5116071656991).

Almost surely, 210232143313981 is an apocalyptic number.

It is an amenable number.

10232143313981 is a deficient number, since it is larger than the sum of its proper divisors (1).

10232143313981 is an equidigital number, since it uses as much as digits as its factorization.

10232143313981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 10232143313981 in words is "ten trillion, two hundred thirty-two billion, one hundred forty-three million, three hundred thirteen thousand, nine hundred eighty-one".