Base | Representation |
---|---|
bin | 11101110001111100001… |
… | …11010010001000110101 |
3 | 10121211011122200212200202 |
4 | 32320332013102020311 |
5 | 113231101021010031 |
6 | 2102023312450245 |
7 | 133632643103561 |
oct | 16707607221065 |
9 | 3554148625622 |
10 | 1023244313141 |
11 | 364a56814446 |
12 | 14638a549985 |
13 | 75650b58a9b |
14 | 3774d5706a1 |
15 | 1b93c2352cb |
hex | ee3e1d2235 |
1023244313141 has 2 divisors, whose sum is σ = 1023244313142. Its totient is φ = 1023244313140.
The previous prime is 1023244313137. The next prime is 1023244313149. The reversal of 1023244313141 is 1413134423201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 906406818916 + 116837494225 = 952054^2 + 341815^2 .
It is an emirp because it is prime and its reverse (1413134423201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1023244313141 - 22 = 1023244313137 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1023244313149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511622156570 + 511622156571.
It is an arithmetic number, because the mean of its divisors is an integer number (511622156571).
Almost surely, 21023244313141 is an apocalyptic number.
It is an amenable number.
1023244313141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1023244313141 is an equidigital number, since it uses as much as digits as its factorization.
1023244313141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1023244313141 its reverse (1413134423201), we get a palindrome (2436378736342).
The spelling of 1023244313141 in words is "one trillion, twenty-three billion, two hundred forty-four million, three hundred thirteen thousand, one hundred forty-one".
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