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10233111413219 is a prime number
BaseRepresentation
bin1001010011101001010011…
…1110001000000111100011
31100020021110010111000020112
42110322110332020013203
52320124403010210334
633433005415401535
72104214016561602
oct224722476100743
940207403430215
1010233111413219
113295924686032
1211932b43832ab
13592c943326a6
142753dc983a39
1512b2c02414ce
hex94e94f881e3

10233111413219 has 2 divisors, whose sum is σ = 10233111413220. Its totient is φ = 10233111413218.

The previous prime is 10233111413183. The next prime is 10233111413243. The reversal of 10233111413219 is 91231411133201.

It is a strong prime.

It is an emirp because it is prime and its reverse (91231411133201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10233111413219 - 224 = 10233094636003 is a prime.

It is a super-3 number, since 3×102331114132193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (10233111412219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5116555706609 + 5116555706610.

It is an arithmetic number, because the mean of its divisors is an integer number (5116555706610).

Almost surely, 210233111413219 is an apocalyptic number.

10233111413219 is a deficient number, since it is larger than the sum of its proper divisors (1).

10233111413219 is an equidigital number, since it uses as much as digits as its factorization.

10233111413219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 32.

The spelling of 10233111413219 in words is "ten trillion, two hundred thirty-three billion, one hundred eleven million, four hundred thirteen thousand, two hundred nineteen".