Base | Representation |
---|---|
bin | 1001010011101010011001… |
… | …0000100000011111010111 |
3 | 1100020022012100020010002211 |
4 | 2110322212100200133113 |
5 | 2320131001232204221 |
6 | 33433054300014251 |
7 | 2104224141031363 |
oct | 224724620403727 |
9 | 40208170203084 |
10 | 10233401444311 |
11 | 3295a63370751 |
12 | 1193375531387 |
13 | 59300c44cb16 |
14 | 2754292c02a3 |
15 | 12b2da9316e1 |
hex | 94ea64207d7 |
10233401444311 has 2 divisors, whose sum is σ = 10233401444312. Its totient is φ = 10233401444310.
The previous prime is 10233401444293. The next prime is 10233401444327. The reversal of 10233401444311 is 11344410433201.
It is a strong prime.
It is an emirp because it is prime and its reverse (11344410433201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10233401444311 - 27 = 10233401444183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10233401444351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5116700722155 + 5116700722156.
It is an arithmetic number, because the mean of its divisors is an integer number (5116700722156).
Almost surely, 210233401444311 is an apocalyptic number.
10233401444311 is a deficient number, since it is larger than the sum of its proper divisors (1).
10233401444311 is an equidigital number, since it uses as much as digits as its factorization.
10233401444311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 10233401444311 its reverse (11344410433201), we get a palindrome (21577811877512).
The spelling of 10233401444311 in words is "ten trillion, two hundred thirty-three billion, four hundred one million, four hundred forty-four thousand, three hundred eleven".
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