Base | Representation |
---|---|
bin | 10011000100110111… |
… | …00101000011001111 |
3 | 222102201212112120122 |
4 | 21202123211003033 |
5 | 131433240101112 |
6 | 4412123135155 |
7 | 511534611026 |
oct | 114233450317 |
9 | 28381775518 |
10 | 10241331407 |
11 | 4385a6795a |
12 | 1b999744bb |
13 | c729b6318 |
14 | 6d22238bd |
15 | 3ee17d872 |
hex | 2626e50cf |
10241331407 has 2 divisors, whose sum is σ = 10241331408. Its totient is φ = 10241331406.
The previous prime is 10241331383. The next prime is 10241331413. The reversal of 10241331407 is 70413314201.
10241331407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (70413314201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10241331407 - 214 = 10241315023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10241331487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5120665703 + 5120665704.
It is an arithmetic number, because the mean of its divisors is an integer number (5120665704).
Almost surely, 210241331407 is an apocalyptic number.
10241331407 is a deficient number, since it is larger than the sum of its proper divisors (1).
10241331407 is an equidigital number, since it uses as much as digits as its factorization.
10241331407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 10241331407 its reverse (70413314201), we get a palindrome (80654645608).
The spelling of 10241331407 in words is "ten billion, two hundred forty-one million, three hundred thirty-one thousand, four hundred seven".
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