Base | Representation |
---|---|
bin | 10111010010010011110101… |
… | …101111010000000101100111 |
3 | 111102121121200120022210200111 |
4 | 113102103311233100011213 |
5 | 101410414441142313112 |
6 | 1001452010414153451 |
7 | 30400055421233263 |
oct | 2722236557200547 |
9 | 442547616283614 |
10 | 102413323010407 |
11 | 2a6a5278a25262 |
12 | b5a047a7b2887 |
13 | 451b6c52b3856 |
14 | 1b40b8d0730a3 |
15 | bc9013b4e5a7 |
hex | 5d24f5bd0167 |
102413323010407 has 2 divisors, whose sum is σ = 102413323010408. Its totient is φ = 102413323010406.
The previous prime is 102413323010393. The next prime is 102413323010423. The reversal of 102413323010407 is 704010323314201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102413323010407 - 215 = 102413322977639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102413323010707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51206661505203 + 51206661505204.
It is an arithmetic number, because the mean of its divisors is an integer number (51206661505204).
Almost surely, 2102413323010407 is an apocalyptic number.
102413323010407 is a deficient number, since it is larger than the sum of its proper divisors (1).
102413323010407 is an equidigital number, since it uses as much as digits as its factorization.
102413323010407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 102413323010407 its reverse (704010323314201), we get a palindrome (806423646324608).
The spelling of 102413323010407 in words is "one hundred two trillion, four hundred thirteen billion, three hundred twenty-three million, ten thousand, four hundred seven".
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