102443312497 has 2 divisors, whose sum is σ = 102443312498. Its totient is φ = 102443312496.

The previous prime is 102443312479. The next prime is 102443312537. The reversal of 102443312497 is 794213344201.

Together with previous prime (102443312479) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (102443312537) can be obtained adding 102443312497 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97633751296 + 4809561201 = 312464^2 + 69351^2 .

It is a cyclic number.

It is not a de Polignac number, because 102443312497 - 2⁷ = 102443312369 is a prime.

It is not a weakly prime, because it can be changed into another prime (102443312467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51221656248 + 51221656249.

It is an arithmetic number, because the mean of its divisors is an integer number (51221656249).

Almost surely, 2^102443312497 is an apocalyptic number.

It is an amenable number.

102443312497 is a deficient number, since it is larger than the sum of its proper divisors (1).

102443312497 is an equidigital number, since it uses as much as digits as its factorization.

102443312497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 40.

Adding to 102443312497 its reverse (794213344201), we get a palindrome (896656656698).

The spelling of 102443312497 in words is "one hundred two billion, four hundred forty-three million, three hundred twelve thousand, four hundred ninety-seven".