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10244331283 is a prime number
BaseRepresentation
bin10011000101001110…
…00001011100010011
3222102221111221122011
421202213001130103
5131440022100113
64412311323351
7511602244024
oct114247013423
928387457564
1010244331283
11438772679a
121b9a980557
13c734c68b4
146d27a4c4b
153ee57263d
hex2629c1713

10244331283 has 2 divisors, whose sum is σ = 10244331284. Its totient is φ = 10244331282.

The previous prime is 10244331239. The next prime is 10244331313. The reversal of 10244331283 is 38213344201.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (38213344201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10244331283 - 29 = 10244330771 is a prime.

It is not a weakly prime, because it can be changed into another prime (10244331883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5122165641 + 5122165642.

It is an arithmetic number, because the mean of its divisors is an integer number (5122165642).

Almost surely, 210244331283 is an apocalyptic number.

10244331283 is a deficient number, since it is larger than the sum of its proper divisors (1).

10244331283 is an equidigital number, since it uses as much as digits as its factorization.

10244331283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 10244331283 its reverse (38213344201), we get a palindrome (48457675484).

The spelling of 10244331283 in words is "ten billion, two hundred forty-four million, three hundred thirty-one thousand, two hundred eighty-three".